some random guy wrote:
I knew this would be dug up!Good job Hora! 
A new army should face the 2 others like they were united against it, and the 2 others should have the same predicament. |
Thanks

Well, yes, but I thought of the new army only facing parts of those armies already there.
Let's make a very easy example, with 3 persons a 100 of the same units (like the other ones with equal defense, attack and evrything..)
Player1 occupies the square with 100 units
Player2 attacks with 100 unit, that would give a hard battle
player3 attacks after player2. With the current rules he would take over the square killing off the on remaining unit, and looses noone...
not instantanious (or something..) battles would give some other scenarios...
ok, then scenario 1: player3 attacks immediately after player2, also with 100 units
he would find two equal armies struggling each other, so half of his army attacks player1, other half player2. Those would have to defend
while continuing their fight with half the force.
So it would look like 3 battles 50:50. If one battle is over, the one remaining unit of the winner would join in on one of the other fights, until only one (or perhaps even two

) units of one player are left...well, he would have won obviously.
now scenario 2:
player 1 and 2 are halfway through their battle when player three arrives
makes 50 players each.
player three would see two equal armies, so split his army 50:50
player1 has now to fight with two enemies, same player3
That inflicts some calculation actually...hmm...oh, ugly
I tried to calculate for a dividing the forces they get actually attacked with, so player 1 divides 25:25, player 2 then must divide 17 to 33, but that inflicts back on player 3, giving an ugly three body problem (I think most of you know that from physics)
after some rounds I got a result, where player1 and 2 defended with their whole army against player3, so exactly what I
didn't want

So it seems, we should go for total size, means players 1 sees 50 and 100, so divides 17:33, same player 2, player 3 stays with 50:50
So that gives battles 17:17, and twice 33:50, giving all in all 0 Survivers for players 1 and 2, with player3 taking the square with aproximatly 40 remaining units (still haven't fully understood the victim calculation

).
A further possibility is to readjust armies during battle, means introducing some steps. That would inflict even more victims on player3 (don't want to calculate victims depending on number of steps

)
So I'd prefer a new calculation each time an army arrives, parting the armies on total starting number of possible targets. Gives the most realistic result and further would inflict smallest calculations at least...
Edited by Hora - 22 Jan 2011 at 13:00